What it does
This page is a circuit board with four resistors and a battery. Drag a resistor onto the top wire and it is in series: the same current goes through it and everything else. Drag it into the box below and it joins the parallel bank: it gets the same voltage as the others in the box and takes its own share of the current. Drag it down to the tray and it is out of the circuit.
As you build, the page works out the equivalent resistance one step at a time (series part, parallel part, total), then the current from the battery, the voltage across the parallel box, the current in each branch and the power. Dots move round the wires, faster where more current flows, so you can see the current split at a junction and join up again.
It follows the Class 10 Science electricity topics (resistors in series and in parallel, the heating effect, electric power and the kilowatt hour) and, with the Level switch on Class 12, the Class 12 Physics current electricity topics (internal resistance, terminal voltage, Kirchhoff’s rules). If you have not met V = IR yet, start with the ohm's law lab; to try bigger circuits with switches and other parts, go on to the circuit simulator.
How to use it
- Choose the battery voltage. 230 V is the voltage of house wiring in India, for working out appliance power and bills.
- Drag the resistors R1 to R4 around the picture, or use the table under it: type each resistance in ohms and pick Series, Parallel or Not used.
- Read Worked out step by step. The table under it gives the voltage across, the current through and the power in each resistor.
- In Energy and the bill, type how many hours a day the circuit is on, for how many days, and the price of one unit (1 kWh). The page gives the energy and the cost.
- Switch the Level to Class 12 to give the battery an internal resistance r. The page then shows the terminal voltage, the volts lost inside the battery and Kirchhoff’s loop rule with your numbers.
Worked example
The page starts with R1 = 10 Ω on the top wire, R2 = 10 Ω and R3 = 15 Ω in the parallel box, and a 6 V battery.
- Parallel box: 1/R_p = 1/10 + 1/15 = 0.1667 per Ω, so R_p = 6 Ω.
- Total: R = 10 + 6 = 16 Ω.
- Current: I = 6 / 16 = 375 mA. R1 has 3.75 V across it; the parallel box has 2.25 V.
- The 375 mA splits: 225 mA through R2 and 150 mA through R3, and 225 + 150 = 375.
- Power: 6 V × 0.375 A = 2.25 W. On for 5 hours a day for 30 days, that is 0.338 kWh, which costs about ₹2.36 at ₹7 a unit.
Tips
- In series the total is always bigger than the biggest resistor; in parallel it is always smaller than the smallest one.
- For two resistors in parallel, product over sum is a quick shortcut: 6 × 3 / (6 + 3) = 2 Ω.
- If nothing is in the circuit the page warns about a short circuit, which is what a fuse protects a house from.
FAQ
Why are houses wired in parallel? Each appliance gets the full 230 V and can be switched on or off without affecting the others. In series, one switched-off lamp would turn everything off.
Is the price per unit real? No, ₹7 is only a starting example. Type the rate from your own bill.
Is anything saved? No. The circuit and your answers stay on this page and are gone when you close it.
Where the numbers come from
- Resistors in series (R = R₁ + R₂ + ...) and in parallel (1/R = 1/R₁ + 1/R₂ + ...), P = VI = I²R, energy in kWh, and Kirchhoff's junction and loop rules with a battery's internal resistance: standard school physics results.
- The price per kWh is a made-up example that you can change; no tariff data is used.
- Checked against an independent Python script (fractions for exact parallel sums, then the currents, voltages and powers) and hand-worked examples such as 6 Ω ∥ 3 Ω = 2 Ω.
Standard scientific values, such as constants, atomic weights and melting points, are facts found in every textbook; we name where ours were checked. If you are an author or publisher and want a value, a credit or a table changed or removed, tell us and we will act quickly.
Last updated 2026-11-09.