Spinning skater: angular momentum and pulling arms in

Pull a skater's arms in and watch the spin speed up while the angular momentum L = Iω stays the same and the kinetic energy rises.

Keep it one tap away for everyday use.

Bookmark Spinning skater?

Press Ctrl + D now. Your browser opens its own bookmark box, where you choose the name and folder.

  1. Set
  2. Pull in
  3. Check
Nothing is uploadedWorks offline once open

Pull the arms in

A teaching model: the body has I = 1 kg m² and no friction. With arms out, the hands are 1 m from the axis.

What stays and what changes

Try this

  • Pull the arms in. I falls, so ω must rise. Look at L: it does not change.
  • If I halves, ω doubles and the kinetic energy doubles too. Who supplied that energy? The skater's muscles, pulling the weights inwards.
  • Set the weights to 0. Now the arms do not matter and nothing changes.
  • Try heavier weights for a bigger effect.

Check yourself

What it does

A spinning body keeps its angular momentum L = I ω as long as nothing twists it from outside. The moment of inertia I depends on where the mass is: the further from the axis, the bigger I. So when a skater pulls her arms in, I falls, and ω must rise to keep L the same.

The kinetic energy is ½ I ω², which equals L² ÷ 2I. With L fixed and I smaller, the energy goes up. It comes from the work her muscles do pulling the arms inwards against the “pull outwards” you feel when spinning. This is a teaching model, not a real skater. To find where the mass is balanced first, see centre of mass, and for rotation with moving along a surface see rolling race.

How to use it

  1. Set the weight in each hand and the starting spin.
  2. Press Pull arms in (or move the r slider yourself) and watch ω, I, L and the kinetic energy.
  3. Arms out takes them back; Pause freezes the picture.

What each setting does

  • Hands from the axis r: how far the weights are from the middle.
  • Spin with arms out ω₀: the speed when r = 1 m.
  • Weight in each hand: more weight means arms matter more.

Worked example

Leave the starting spin at 2 rad/s and the weights at 2 kg. With arms out, I = 1 + 2 × 2 × 1² = 5 kg m², so L = 5 × 2 = 10 kg m²/s and the kinetic energy is ½ × 5 × 2² = 10 J.

Pull the hands in to r = 0.5 m. Now I = 1 + 2 × 2 × 0.5² = 2 kg m². L is still 10, so ω = 10 ÷ 2 = 5 rad/s, and the kinetic energy is ½ × 2 × 5² = 25 J.

FAQs

Where does the extra energy come from? From the skater: her muscles do work moving the weights inwards.

Is the angular momentum really constant? Yes, in this model there is no friction or outside twist, so L cannot change.

What if the weights are zero? Then the arms hardly matter in the model, so I stays 1 kg m² and nothing changes.

Is anything stored? No. Everything is worked out in your browser.

Where the numbers come from

  • Conservation of angular momentum, I = ΣmR² and rotational kinetic energy ½Iω²: standard Class 11 physics (system of particles and rotational motion). The skater is fibub's own teaching model: a body of I = 1 kg m² holding two weights.

Standard scientific values, such as constants, atomic weights and melting points, are facts found in every textbook; we name where ours were checked. If you are an author or publisher and want a value, a credit or a table changed or removed, tell us and we will act quickly.

Read more on the Blog

Last updated 2026-11-10.

Change log for Spinning skater

  1. Add spinning-skater (Class 11 Physics) Details on GitHub

Every change to fibub

Related tools